# 接口接收文件,写入文件
@ResponseBody
@PostMapping("/upload")
public ResponseVo upload(@RequestParam(value = "file", required = false) MultipartFile multipartFile) {
File file=new File("上传到服务器的文件地址");
try {
FileUtil.copy(multipartFile.getBytes(), file);
} catch (IOException e) {
return ResultUtil.error();
}
return ResultUtil.success();
}
# httpClient转发上传文件
简单描述我的需求:封装一个公共接口,调用其他系统的接口做文件上传
1 引入hutool的依赖
<!-- hutool 工具包 -->
<dependency>
<groupId>cn.hutool</groupId>
<artifactId>hutool-all</artifactId>
<version>5.7.7</version>
</dependency>
<!-- fastjson工具包 -->
<dependency>
<groupId>com.alibaba</groupId>
<artifactId>fastjson</artifactId>
<version>1.1.23</version>
</dependency>
2 编写controller代码
@ApiOperation(value = "公共文件上传")
@PostMapping(value = "/commons/fileUpload")
public JSONObject fileUpload(MultipartFile file) throws Exception {
return webPostAccountingService.fileUpload(file);
}
3 编写service代码
这里的代码是核心,整个url请求,以及参数都这这里处理的,代码如下
private JSONObject fileUpload(MultipartFile multipartFile) throws Exception {
HashMap<String, Object> paramMaps = new HashMap<>(4);
paramMaps.put("xxx", );
// 将MultipartFile转换为File
paramMaps.put("file", this.multipartFileToFile(multipartFile));
HttpResponse response = HttpRequest.post("xxx")
.header("xxx", xx)
.form(paramMaps)
.execute();
int status = response.getStatus();
System.out.println("请求响应状态码:" + status);
String body = response.body();
System.out.println(body);
JSONObject jsonObject = JSONObject.parseObject(body);
Object msg = jsonObject.get("msg");
System.out.println(msg);
Object code = jsonObject.get("code");
System.out.println(code);
return jsonObject;
}
4 将MultipartFile转换为File方法
所以需要将MultipartFile转换为File,方法如下
private File multipartFileToFile(MultipartFile multiFile) {
// 获取文件名
String fileName = multiFile.getOriginalFilename();
// 获取文件后缀
String prefix = fileName.substring(fileName.lastIndexOf("."));
// 若须要防止生成的临时文件重复,能够在文件名后添加随机码
try {
File file = File.createTempFile(fileName, prefix);
multiFile.transferTo(file);
return file;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}